3x^2+6x-85=0

Solution for 3x^2+6x-85=0 equation:

3x^2+6x-85=0

a = 3; b = 6; c = -85;
Δ = b2-4ac
Δ = 62-4·3·(-85)
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{66}}{2*3}=\frac{-6-4\sqrt{66}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{66}}{2*3}=\frac{-6+4\sqrt{66}}{6}
$